Hasil dari perkalian (3√2–√6)√6
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Materi : Bentuk Akar dan Pangkat
√6( 3√2 - √6 )
= 3√(2×6) - [√6]²
= 3√(4×3) - 6
= (3×2)√3 - 6
= 6√3 - 6
= 6( √3 - 1 )
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
= (3√2 - √6)√6
= 3√12 - 6
= 3√(4 × 3) - 6
= 6√3 - 6
[answer.2.content]
